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Poland Contests
Poland - Second Round
1995 Poland - Second Round
1
1
Part of
1995 Poland - Second Round
Problems
(1)
P(5) is divisible by 2,P(2) is divisible by 5 then P(7) is divisible by 10
Source: Polish second round 1995 p1
1/19/2020
For a polynomial
P
P
P
with integer coefficients,
P
(
5
)
P(5)
P
(
5
)
is divisible by
2
2
2
and
P
(
2
)
P(2)
P
(
2
)
is divisible by
5
5
5
. Prove that
P
(
7
)
P(7)
P
(
7
)
is divisible by
10
10
10
.
Integer Polynomial
polynomial
divisible
algebra