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National and Regional Contests
Poland Contests
Poland - Second Round
1999 Poland - Second Round
1
1
Part of
1999 Poland - Second Round
Problems
(1)
f(1/n) = (−1)^n, there are no increasing functions such f = g - h
Source: Polish second round 1999 p1
1/19/2020
Let
f
:
(
0
,
1
)
→
R
f : (0,1) \to R
f
:
(
0
,
1
)
→
R
be a function such that
f
(
1
/
n
)
=
(
−
1
)
n
f(1/n) = (-1)^n
f
(
1/
n
)
=
(
−
1
)
n
for all n ∈ N. Prove that there are no increasing functions
g
,
h
:
(
0
,
1
)
→
R
g,h : (0,1) \to R
g
,
h
:
(
0
,
1
)
→
R
such that
f
=
g
−
h
f = g - h
f
=
g
−
h
.
function
Increasing function
algebra