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Problems
Contests
National and Regional Contests
Poland Contests
Poland - Second Round
2018 Poland - Second Round
5
5
Part of
2018 Poland - Second Round
Problems
(1)
5-element subsets
Source: 69 Polish MO 2018 Second Round - Problem 5
4/28/2018
Let
A
1
,
A
2
,
.
.
.
,
A
k
A_1, A_2, ..., A_k
A
1
,
A
2
,
...
,
A
k
be
5
5
5
-element subsets of set
{
1
,
2
,
.
.
.
,
23
}
\{1, 2, ..., 23\}
{
1
,
2
,
...
,
23
}
such that, for all
1
≤
i
<
j
≤
k
1 \le i < j \le k
1
≤
i
<
j
≤
k
set
A
i
∩
A
j
A_i \cap A_j
A
i
∩
A
j
has at most three elements. Show that
k
≤
2018
k \le 2018
k
≤
2018
.
combinatorics
set theory
pigeonhole principle
Poland
counting