Let [ABC] be a acute-angled triangle and its circumscribed circle Γ. Let D be the point on the line AB such that A is the midpoint of the segment [DB] and P is the point of intersection of CD with Γ. Points W and L lie on the smaller arcs \overarc{BC} and \overarc{AB}, respectively, and are such that \overarc{BW} = \overarc{LA }= \overarc{AP}. The LC and AW lines intersect at Q. Shows that LQ=BQ. geometrycircumcircleequal segments