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Part of 2006 All-Russian Olympiad
Problems(2)
Symmetric non-self-intersecting path in 15*15 chessboard
Source: All-Russian Olympiad 2006 finals, problem 10.1 = 9.1
5/7/2006
Given a chessboard. We draw a closed broken line without self-intersections such that every edge of the broken line is a segment joining the centers of two adjacent cells of the chessboard. If this broken line is symmetric with respect to a diagonal of the chessboard, then show that the length of the broken line is .
combinatorics proposedcombinatorics
Sin sqrt(x) < sqrt(sin x) for 0 < x < pi/2
Source: All-Russian Olympiad 2006 finals, problem 11.1
5/6/2006
Prove that for every real such that .
trigonometryfunctioncalculusderivativeinequalitiesreal analysisreal analysis unsolved