MathDB

Problems(3)

Similarity appearing from nowhere

Source: All-Russian 2021/9.4

4/19/2021
Given an acute triangle ABCABC, point DD is chosen on the side ABAB and a point EE is chosen on the extension of BCBC beyond CC. It became known that the line through EE parallel to ABAB is tangent to the circumcircle of ADC\triangle ADC. Prove that one of the tangents from EE to the circumcircle of BCD\triangle BCD cuts the angle ABE\angle ABE in such a way that a triangle similar to ABC\triangle ABC is formed.
geometry
existence of some cards

Source: All-Russian 2021/10.4

4/19/2021
Given a natural number n>4n>4 and 2n+42n+4 cards numbered with 1,2,,2n+41, 2, \dots, 2n+4. On the card with number mm a real number ama_m is written such that am=m\lfloor a_{m}\rfloor=m. Prove that it's possible to choose 44 cards in such a way that the sum of the numbers on the first two cards differs from the sum of the numbers on the two remaining cards by less than 1nn2\frac{1}{n-\sqrt{\frac{n}{2}}}.
combinatoricsRussiaAll Russian Olympiad
angle bisectors and two congruent angles

Source: All-Russian 2021/11.4

4/20/2021
In triangle ABCABC angle bisectors AA1AA_{1} and CC1CC_{1} intersect at II. Line through BB parallel to ACAC intersects rays AA1AA_{1} and CC1CC_{1} at points A2A_{2} and C2C_{2} respectively. Let OaO_{a} and OcO_{c} be the circumcenters of triangles AC1C2AC_{1}C_{2} and CA1A2CA_{1}A_{2} respectively. Prove that OaBOc=AIC\angle{O_{a}BO_{c}} = \angle{AIC}
geometryangle bisectorcircumcircle