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National and Regional Contests
Russia Contests
Assara - South Russian Girl's MO
2023 Assara - South Russian Girl's MO
2023 Assara - South Russian Girl's MO
Part of
Assara - South Russian Girl's MO
Subcontests
(8)
8
2
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n-gon's perimeter > 2n-gon's perimeter, perimeters ACE=ABCDEF
a) Given a convex hexagon
A
B
C
D
E
F
ABCDEF
A
BC
D
EF
, which has a center of symmetry. Prove that the perimeter of triangle
A
C
E
ACE
A
CE
is greater than half the perimeter of hexagon
A
B
C
D
E
F
ABCDEF
A
BC
D
EF
.b) Given a convex
(
2
n
)
(2n)
(
2
n
)
-gon
P
P
P
having a center of symmetry, its vertices are colored alternately red and blue. Let
Q
Q
Q
be an
n
n
n
-gon with red vertices. Is it possible to say that the perimeter of
Q
Q
Q
is certainly greater than half the perimeter
P
P
P
? Solve the problem for
n
=
4
n = 4
n
=
4
and
n
=
5
n = 5
n
=
5
.
sequence of letters ASSARA...
The girl continues the sequence of letters
A
S
S
A
R
A
.
.
.
ASSARA...
A
SS
A
R
A
...
, adding one of the three letters
A
A
A
,
R
R
R
or
S
S
S
. When adding the next letter, the girl makes sure that no two written sevens of consecutive letters coincide. At some point it turned out that it was impossible to add a new letter according to these rules. What letter could be written last?
7
2
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increasing sequence , a_n = 2023
Given an increasing sequence of different natural numbers
a
1
<
a
2
<
a
3
<
.
.
.
<
a
n
a_1 < a_2 < a_3 < ... < a_n
a
1
<
a
2
<
a
3
<
...
<
a
n
such that for any two distinct numbers in this sequence their sum is not divisible by
10
10
10
. It is known that
a
n
=
2023
a_n = 2023
a
n
=
2023
. a) Can
n
n
n
be greater than
800
800
800
? b) What is the largest possible value of
n
n
n
? c) For the value
n
n
n
found in question b), find the number of such sequences with
a
n
=
2023
a_n = 2023
a
n
=
2023
.
midpoint of median drawn from vertex A lies on axis of parabola
A parabola is drawn on the coordinate plane - the graph of a square trinomial. The vertices of triangle
A
B
C
ABC
A
BC
lie on this parabola so that the bisector of angle
∠
B
A
C
\angle BAC
∠
B
A
C
is parallel to the axis
O
x
Ox
O
x
. Prove that the midpoint of the median drawn from vertex
A
A
A
lies on the axis of the parabola.
6
2
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14 wheels of cheese and a scale
Aunt Raya has
14
14
14
wheels of cheese. She found out that out of any
6
6
6
wheels, she could choose
4
4
4
and put them on the scales so that the scales came into balance. Aunt Raya wants to give Daud Kazbekovich two of these
14
14
14
wheels , and divide the rest equally (by weight) between Pavel and Kirill. Prove that she can make her wish come true.
gray cells in 5x9 table (senior version of 5x5 junior)
In a
5
×
9
5 \times 9
5
×
9
checkered rectangle, the middle row and middle column are colored gray. You leave the corner cell and move to the cell adjacent to the side with each move. For each transition from a gray cell to a gray one you need to pay a ruble. What is the smallest number of rubles you need to pay to go around all the squares of the board exactly once (it is not necessary to return to the starting square)?
5
2
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gray cells in 5x5 table
In a
5
×
5
5 \times 5
5
×
5
checkered square, the middle row and middle column are colored gray. You leave the corner cell and move to the cell adjacent to the side with each move. For each transition from a gray cell to a gray one you need to pay a ruble. What is the smallest number of rubles you need to pay to go around all the squares of the board exactly once (it is not necessary to return to the starting square)?
a + b + c =? if |a - b| + |b - c| + |c - a| = 1
Given three non-negative real numbers
a
a
a
,
b
b
b
and
c
c
c
. The sum of the modules of their pairwise differences is equal to
1
1
1
, i.e.
∣
a
−
b
∣
+
∣
b
−
c
∣
+
∣
c
−
a
∣
=
1
|a- b| + |b -c| + |c -a| = 1
∣
a
−
b
∣
+
∣
b
−
c
∣
+
∣
c
−
a
∣
=
1
. What can the sum
a
+
b
+
c
a + b + c
a
+
b
+
c
be equal to?
4
2
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100 colors for 50x50 table, 1x2 tile related condition
In a
50
×
50
50 \times 50
50
×
50
checkered square, each cell is painted in one of
100
100
100
given colors so that all colors are present and it is impossible to cut a single-color domino from the square (i.e. a
1
×
2
1 \times 2
1
×
2
rectangle). Galiia wants to recolor all the cells of one of the colors into another color (out of the given
100
100
100
colors) so that this condition is preserved (i.e., it is still impossible to cut out a domino of the same color). Is it true that Galiia will definitely be able to do this?
CD // AB, starting with equal intersecting circles
Two equal circles
Ω
1
\Omega_1
Ω
1
and
Ω
2
\Omega_2
Ω
2
intersect at points
A
A
A
and
B
B
B
, and
M
M
M
is the midpoint of
A
B
AB
A
B
. Two rays were drawn from
M
M
M
, lying in the same half-plane wrt
A
B
AB
A
B
(see figure). The first ray intersects the circles
Ω
1
\Omega_1
Ω
1
and
Ω
2
\Omega_2
Ω
2
at points
X
1
X_1
X
1
and
X
2
X_2
X
2
, and the second ray intersects them at points
Y
1
Y_1
Y
1
and
Y
2
Y_2
Y
2
, respectively. Let
C
C
C
be the intersection point of straight lines
A
X
1
AX_1
A
X
1
and
B
Y
2
BY_2
B
Y
2
, and let
D
D
D
be the intersection point of straight lines
A
X
2
AX_2
A
X
2
and
B
Y
1
BY_1
B
Y
1
. Prove that
C
D
∥
A
B
CD \parallel AB
C
D
∥
A
B
. https://cdn.artofproblemsolving.com/attachments/4/a/fae047c3956d8b30f15a9d88e8d12e5f4d48ec.png
3
1
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1 * 2 * 3 * 4 * 5 * ... * 60 * 61 * 62 = 2023, use + ., - or x
In equality
1
∗
2
∗
3
∗
4
∗
5
∗
.
.
.
∗
60
∗
61
∗
62
=
2023
1 * 2 * 3 * 4 * 5 * ... * 60 * 61 * 62 = 2023
1
∗
2
∗
3
∗
4
∗
5
∗
...
∗
60
∗
61
∗
62
=
2023
Instead of each asterisk, you need to put one of the signs “+” (plus), “-” (minus), “•” (multiply) so that the equality becomes true. What is the smallest number of "•" characters that can be used?
2
2
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< AXC=? AC = BD, <ABX = <AX B = 50^o, <CAD = 51^o, <AED = 80^o
In the convex quadrilateral
A
B
C
D
ABCD
A
BC
D
, point
X
X
X
is selected on side
A
D
AD
A
D
, and the diagonals intersect at point
E
E
E
. It is known that
A
C
=
B
D
AC = BD
A
C
=
B
D
,
∠
A
B
X
=
∠
A
X
B
=
5
0
o
\angle ABX = \angle AX B = 50^o
∠
A
BX
=
∠
A
XB
=
5
0
o
,
∠
C
A
D
=
5
1
o
\angle CAD = 51^o
∠
C
A
D
=
5
1
o
,
∠
A
E
D
=
8
0
o
\angle AED = 80^o
∠
A
E
D
=
8
0
o
. Find the value of angle
∠
A
X
C
\angle AXC
∠
A
XC
.
a^a is divisible by b^b
The natural numbers
a
a
a
and
b
b
b
are such that
a
a
a^a
a
a
is divisible by
b
b
b^b
b
b
. Can we say that then
a
a
a
is divisible by
b
b
b
?
1
2
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percentages in a survey
A survey of participants was conducted at the Olympiad.
50
%
50\%
50%
of the participants liked the first round,
60
%
60\%
60%
of the participants liked the second round,
70
%
70\%
70%
of the participants liked the opening of the Olympiad. It is known that each participant liked either one option or all three. Determine the percentage of participants who rated all three events positively.
percentages in a survey , senior version
A survey of participants was conducted at the Olympiad.
90
%
90\%
90%
of the participants liked the first round,
60
%
60\%
60%
of the participants liked the second round,
90
%
90\%
90%
of the participants liked the opening of the Olympiad. Each participant was known to enjoy at least two of these three events. Determine the percentage of participants who rated all three events positively.