MathDB

7

Part of 2006 Junior Tuymaada Olympiad

Problems(1)

prove PQ> AC related to intersections of lines with circumcircles

Source: Tuymaada Junior 2006 p7

5/12/2019
The median BM BM of a triangle ABC ABC intersects the circumscribed circle at point K K . The circumcircle of the triangle KMC KMC intersects the segment BC BC at point P P , and the circumcircle of AMK AMK intersects the extension of BA BA at Q Q . Prove that PQ>AC PQ> AC .
geometrycircumcirclemediangeometric inequality