MathDB

178

Part of 1950 Moscow Mathematical Olympiad

Problems(1)

MMO 178 Moscow MO 1950 sinx =(sinBsinC)/(1 - cosB cosCcosA)

Source:

8/6/2019
Let AA be an arbitrary angle,let BB and CC be acute angles. Is there an angle xx such that sin⁡x=sin⁡B⋅sin⁡C1−cos⁡B⋅cos⁡C⋅cos⁡A?\sin x =\frac{\sin B \cdot \sin C}{1 - \cos B \cdot \cos C \cdot \cos A} ?
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