4
Part of 2008 Sharygin Geometry Olympiad
Problems(4)
Triangle and two angles
Source: Sharygin contest. The final raund. 2008. Grade 8. First day. Problem 4
8/31/2008
(F.Nilov, A.Zaslavsky) Let be a median of triangle ; the perpendicular bisectors to and intersect in points , ; is the meet of lines and . Prove that \angle C_1CA \equal{} \angle C_0CB.
symmetrygeometryparallelogramangle bisectorgeometry unsolved
Circle passes through the circumcenter
Source: Sharygin contest. The final raund. 2008. Grade 9. First day. Problem 4
8/31/2008
(F.Nilov, A.Zaslavsky) Let be a median of triangle ; the perpendicular bisectors to and intersect in points , ; is the common point of and . Points , are defined similarly. Prove that circle passes through the circumcenter of triangle .
geometrycircumcircleangle bisectorgeometry unsolved
Locus of incenters of triangles
Source: Sharygin contest. The final raund. 2008. Grade 10. First day. Problem 4
8/31/2008
(A.Zaslavsky) Given three points , , on the line . Find the locus of incenters of triangles such that points , lie on and the feet of the median, the bisector and the altitude from coincide with , , .
geometryincentergeometry unsolved
Sum of squares of some two sides
Source: Sharygin contest 2008. The correspondence round. Problem 4
9/3/2008
(D.Shnol, 8--9) The bisectors of two angles in a cyclic quadrilateral are parallel. Prove that the sum of squares of some two sides in the quadrilateral equals the sum of squares of two remaining sides.
geometrycyclic quadrilateralgeometry proposed