MathDB

18

Part of 2013 Sharygin Geometry Olympiad

Problems(1)

Prove that angle BAX = angle CAY

Source: Sharygin First Round 2013, Problem 18

4/8/2013
Let ADAD be a bisector of triangle ABCABC. Points MM and NN are projections of BB and CC respectively to ADAD. The circle with diameter MNMN intersects BCBC at points XX and YY. Prove that ∠BAX=∠CAY\angle BAX = \angle CAY.
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