2
Part of 2014 Sharygin Geometry Olympiad
Problems(4)
Possible 12-Gon Construction?
Source: Sharygin Geometry Olympiad 2014 - Problem 2
11/15/2014
A paper square with sidelength is given. From this square, can we cut out a -gon having all sidelengths equal to and all angles divisible by ?
geometry unsolvedgeometry
in a quadrilateral with 2 opposite angles right ... a line bisects a segment
Source: 2014 Sharygin Geometry Olympiad Final Round 9.2
8/3/2018
In a quadrilateral angles and are right. Two circles with diameters and meet at points and . Prove that line passes through the midpoint of .(F. Nilov )
circlesgeometry
segments of feet of altitudes // segment of feet of angle biectors, isosceles ?
Source: 2014 Sharygin Geometry Olympiad Final Round 8.2
8/3/2018
Let and be altitudes, and be angle bisectors of a triangle . It is known that . Is it necessarily true that ?(B. Frenkin)
geometryisosceles
intesecting tangents to create a segment of constant length
Source: 2014 Sharygin Geometry Olympiad Final Round 10.2
8/3/2018
A circle, its chord and the midpoint of the minor arc are given. Take an arbitrary point on the major arc . The tangent to the circle at meets the tangents at and at points and respectively. Lines and WY meet AB at points and respectively. Prove that the length of segment does not depend on point .(A. Zertsalov, D. Skrobot)
geometrytangentconstantSegment