In a parallelogram ABCD the trisectors of angles A and B are drawn. Let O be the common points of the trisectors nearest to AB. Let AO meet the second trisector of angle B at point A1, and let BO meet the second trisector of angle A at point B1. Let M be the midpoint of A1B1. Line MO meets AB at point N Prove that triangle A1B1N is equilateral. parallelogramgeometryanglesEquilateral Triangle