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9.8

Part of VII Soros Olympiad 2000 - 01

Problems(1)

locus of circumcenters 2<B_1A_1C_1+<BAC = 180^o(VII Soros Olympiad R1 9.8)

Source:

7/4/2021
Given a triangle ABCABC. On its sides BCBC , CACA and ABAB , the points A1A_1 , B1B_1 and C1C_1 are taken, respectively , such that 2∠B1A1C1+∠BAC=180o2 \angle B_1 A_1 C_1 + \angle BAC = 180^o , 2∠A1C1B1+∠ACB=180o2 \angle A_1 C_1 B_1 + \angle ACB = 180^o , 2∠C1B1A1+∠CBA=180o2 \angle C_1 B_1 A_1 + \angle CBA = 180^o . Find the locus of the centers of the circles circumscribed about the triangles A1B1C1A_1 B_1 C_1 (all possible such triangles are considered).
geometryanglesLocusCircumcenter