Let ABC be a right triangle with ∠ACB=90o and M the center of AB. Let G br any point on the line MC and P a point on the line AG, such that ∠CPA=∠BAC . Further let Q be a point on the straight line BG, such that ∠BQC=∠CBA . Show that the circles of the triangles AQG and BPG intersect on the segment AB. equal anglesconcurrencyconcurrentgeometry