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Switzerland - Final Round
2022 Switzerland - Final Round
2
2
Part of
2022 Switzerland - Final Round
Problems
(1)
1^1, 3^3, 5^5, ..., (2n-1)^{2n-1} different remainders divided by 2^n
Source: Switzerland - 2022 Swiss Final Round p2
11/17/2022
Let
n
n
n
be a positive integer. Prove that the numbers
1
1
,
3
3
,
5
5
,
.
.
.
,
(
2
n
−
1
)
2
n
−
1
1^1, 3^3, 5^5, ..., (2n-1)^{2n-1}
1
1
,
3
3
,
5
5
,
...
,
(
2
n
−
1
)
2
n
−
1
all give different remainders when divided by
2
n
2^n
2
n
.
number theory
remainder
divides