Subcontests
(5)Polynomial with power of two
Let n be an odd number larger than 1, and f(x) is a polynomial with degree n such that f(k)=2k for k=0,1,⋯,n. Prove that there is only finite integer x such that f(x) is the power of two. Inequality from 2017 Taiwan TST
Given a,b,c,d>0, prove that:
cyc∑a+2bc+cyc∑ca+2b≥8(ab+ac+ad+bc+bd+cd(a+b+c+d)2−1),
where ∑cycf(a,b,c,d)=f(a,b,c,d)+f(d,a,b,c)+f(c,d,a,b)+f(b,c,d,a). Easy number theory 2017 Taiwan TST
For postive integers k,n, let
fk(n)=m∣n,m>0∑mk
Find all pairs of positive integer (a,b) such that fa(n)∣fb(n) for every positive integer n.