Subcontests
(6)A delicious geometry in Taiwan TST
Let Ω be the circumcircle of an acute triangle ABC. Points D, E, F are the midpoints of the inferior arcs BC, CA, AB, respectively, on Ω. Let G be the antipode of D in Ω. Let X be the intersection of lines GE and AB, while Y the intersection of lines FG and CA. Let the circumcenters of triangles BEX and CFY be points S and T, respectively. Prove that D, S, T are collinear.
Proposed by kyou46 and Li4. Joints type inequality
For each positive integer k greater than 1, find the largest real number t such that the following hold:
Given n distinct points a(1)=(a1(1),…,ak(1)), …, a(n)=(a1(n),…,ak(n)) in Rk, we define the score of the tuple a(i) as
j=1∏k#{1≤i′≤n such that πj(a(i′))=πj(a(i))}
where #S is the number of elements in set S, and πj is the projection Rk→Rk−1 omitting the j-th coordinate. Then the t-th power mean of the scores of all a(i)'s is at most n.Note: The t-th power mean of positive real numbers x1,…,xn is defined as
(nx1t+⋯+xnt)1/t
when t=0, and it is nx1⋯xn when t=0.Proposed by Cheng-Ying Chang and usjl