Let ABC be a triangle such that AC>AB. A circle tangent to the sides AB and AC at D and E respectively, intersects the circumcircle of ABC at K and L. Let X and Y be points on the sides AB and AC respectively, satisfying
\frac{AX}{AB}=\frac{CE}{BD+CE} \text{and} \frac{AY}{AC}=\frac{BD}{BD+CE}
Show that the lines XY,BC and KL are concurrent. geometrycircumcirclegeometry proposed