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Turkey Team Selection Test
2016 Turkey Team Selection Test
4
4
Part of
2016 Turkey Team Selection Test
Problems
(1)
Polynomial Having Values of a Sequence
Source: Turkey TST 2016 P4
4/10/2016
A sequence of real numbers
a
0
,
a
1
,
…
a_0, a_1, \dots
a
0
,
a
1
,
…
satisfies the condition
∑
n
=
0
m
a
n
⋅
(
−
1
)
n
⋅
(
m
n
)
=
0
\sum\limits_{n=0}^{m}a_n\cdot(-1)^n\cdot\dbinom{m}{n}=0
n
=
0
∑
m
a
n
⋅
(
−
1
)
n
⋅
(
n
m
)
=
0
for all large enough positive integers
m
m
m
. Prove that there exists a polynomial
P
P
P
such that
a
n
=
P
(
n
)
a_n=P(n)
a
n
=
P
(
n
)
for all
n
≥
0
n\ge0
n
≥
0
.
algebra
polynomial