MathDB

2008.9.5

Part of Kyiv City MO Juniors 2003+ geometry

Problems(1)

<BFL=?AF=LC<1/2AC, AB^2+BC^2=AL^2+LC^2 (Kyiv City Olympiad 2008 9.5)

Source:

6/30/2020
In the triangle ABCABC on the side ACAC the points FF and LL are selected so that AF=LC<12ACAF = LC <\frac{1}{2} AC. Find the angle ∠FBL \angle FBL if AB2+BC2=AL2+LC2A {{B} ^ {2}} + B {{C} ^ {2}} = A {{L} ^ {2}} + L {{C } ^ {2}}
(Zhidkov Sergey)
geometryangles