Let H be the intersection point of the altitudes AP and CQ of the acute-angled triangle ABC. On its median BM marked points E and F so that ∠APE=∠BAC and ∠CQF=∠BCA, and the point E lies inside the triangle APB, and the point F lies inside the triangle CQB. Prove that the lines AE, CF and BH intersect at one point.(Vyacheslav Yasinsky) geometryequal anglesconcurrencyconcurrent