Inside the triangle ABC choose the point M, and on the side BC - the point K in such a way that MK∣∣AB. The circle passing through the points M,K,C, crosses the side AC for the second time at the point N, a circle passing through the points M,N,A, crosses the side AB for the second time at the point Q. Prove that BM=KQ.(Nagel Igor) geometryequal segmentsparallelcircles