On the circle with diameter AB, the point M was selected and fixed. Then the point Qi is selected, for which the chord MQi intersects AB at the point Ki and thus ∠MKiB<90∘. A chord that is perpendicular to AB and passes through the point Ki intersects the line BQi at the point Pi. Prove that the points Pi in all possible choices of the point Qi lie on the same line.(Igor Nagel)
geometryLocuscirclecollinear