MathDB

2017.10.3

Part of Kyiv City MO Seniors 2003+ geometry

Problems(1)

AB = AH wanted inside a square ABCD (2017 Kyiv City MO 10.3)

Source:

9/9/2020
Given the square ABCDABCD. Let point MM be the midpoint of the side BCBC, and HH be the foot of the perpendicular from vertex CC on the segment DMDM. Prove that AB=AHAB = AH.
(Danilo Hilko)
geometrysquareequal segments