MathDB

2005.7

Part of Ukraine Correspondence MO - geometry

Problems(1)

<AOE =? trapezoid ABCD, EF//AB , EF = AD, <AOB=<DAB=90^o

Source: 2005 All-Ukrainian Correspondence MO of magazine ''In the World of Mathematics'', grades 5-11 p7

4/28/2021
Let OO be the point of intersection of the diagonals of the trapezoid ABCDABCD with the bases ABAB and CDCD. It is known that ∠AOB=∠DAB=90o\angle AOB = \angle DAB = 90^o. On the sides ADAD and BCBC take the points EE and FF so that EF∥ABEF\parallel AB and EF=ADEF = AD. Find the angle ∠AOE\angle AOE.
geometrytrapezoidanglesright angleUkraine Correspondence