MathDB

2010.7

Part of Ukraine Correspondence MO - geometry

Problems(1)

BE = AD if DE// AB , CE // BM, D in median BM

Source: 2010 All-Ukrainain Correspondence MO of magazine ''In the World of Mathematics'', grades 5-12 p7

4/26/2021
An arbitrary point DD was marked on the median BMBM of the triangle ABCABC. It is known that the point DE∥ABDE\parallel AB and CE∥BMCE \parallel BM. Prove that BE=ADBE = AD
geometryequal segmentsparallelUkraine Correspondence