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Ukrainian From Tasks to Tasks - geometry
2011.3
2011.3
Part of
Ukrainian From Tasks to Tasks - geometry
Problems
(1)
AP=AB wanted, circumcenter, bisector (2011 From Tasks to Tasks, p3 Ukr)
Source:
5/2/2021
Let
O
O
O
be the center of the circumcircle, and
A
D
AD
A
D
be the angle bisector of the acute triangle
A
B
C
ABC
A
BC
. The perpendicular drawn from point
D
D
D
on the line
A
O
AO
A
O
intersects the line
A
C
AC
A
C
at the point
P
P
P
. Prove that
A
P
=
A
B
AP = AB
A
P
=
A
B
.
geometry
equal segments
Circumcenter