Let ABC be a triangle with two angles B,C not having the same measure, I be its incircle, (O) its circumcircle. Circle (Ob) touches BA,BC and is internally tangent to (O) at B1. Circle (Oc) touches CA,CB and is internally tangent to (O) at C1. Let S be the intersection of BC and B1C1. Prove that ∠AIS=90o.Nguyễn Minh Hà geometryright angleincirclecircumcircletangent circles