Let P be an arbitrary point in the plane of triangle ABC. Lines PA,PB,PC meets the perpendicular bisectors of BC,CA,AB at Oa,Ob,Oc respectively. Let (Oa) be the circle with center Oa passing through two points B,C, two circles (Ob),(Oc) are defined in the same manner. Two circles (Ob),(Oc) meets at A1, distinct from A. Points B1,C1 are defined in the same manner. Let Q be an arbitrary point in the plane of ABC and QB,QC meets (Oc) and (Ob) at A2,A3 distinct from B,C. Similarly, we have points B2,B3,C2,C3. Let (Ka),(Kb),(Kc) be the circumcircles of triangles A1A2A3,B1B2B3,C1C2C3. Prove that
(a) three circles (Ka),(Kb),(Kc) have a common point.
(b) two triangles KaKbKc,ABC are similar.Trần Quang Hùng similarconcurrent circlesconcurrentcirclesgeometrysimilar triangles