MathDB

Problems(4)

{(a, b, c) | ab + bc + ca> 0} when a <k (b + c), b <k (c + a) , c <k (a + b)

Source: Mathley 2014.1 p4

8/19/2020
Let SkS_k be the set of all triplets of real numbers (a,b,c)(a, b, c) satisfying a<k(b+c)a <k (b + c), b<k(c+a)b <k (c + a), and c<k(a+b)c <k (a + b). For what value of kk then SkS_k is a subset of {(a,b,c)ab+bc+ca>0}\{(a, b, c) | ab + bc + ca> 0\} ?
Michel Bataille, France
algebrainequalities
common tangent of 3 circles wanted, mixtilinear circles related

Source: Mathley 2014.2 p4

8/20/2020
Let (O)(O) be the circumcircle of triangle ABCABC, and PP a point on the arc BCBC not containing AA. (Q)(Q) is the AA-mixtilinear circle of triangle ABCABC, and (K),(L)(K), (L) are the PP-mixtilinear circles of triangle PAB,PACPAB, PAC respectively. Prove that there is a line tangent to all the three circles (Q),(K)(Q), (K) and (L)(L).
Nguyen Van Linh, a student at Hanoi Foreign Trade University Cabinet
geometrycommon tangentmixtilinear
perpendicular wanted, reflections of B,C across AC,AB , circumcircle

Source: Mathley 2014.3 p4

8/18/2020
Let ABCABC be an acute triangle with E,FE, F being the reflections of B,CB,C about the line AC,ABAC, AB respectively. Point DD is the intersection of BFBF and CECE. If KK is the circumcircle of triangle DEFDEF, prove that AKAK is perpendicular to BCBC.
Nguyen Minh Ha, College of Pedagogical University of Hanoi
geometrygeometric transformationreflectioncircumcircle
MN passes through circumcenter of ABC, BE = AE, AF = CF, orthocenter

Source: Mathley 2015 p4

8/18/2020
Points E,FE, F are in the plane of triangle ABCABC so that triangles ABEABE and ACFACF are the opposite directed, and the two triangles are isosceles in that BE=AE,AF=CFBE = AE, AF = CF. Let H,KH, K be the orthocenter of triangle ABE,ACFABE, ACF respectively. Points M,NM, N are the intersections of BEBE and CF,CKCF, CK and CHCH. Prove that MNMN passes through the center of the circumcircle of triangle ABCABC.
Nguyen Minh Ha, High School for Education, Hanoi Pedagogical University
Circumcenterequal segmentsorthocenterisoscelestrigonometry