6
Part of 2004 IMC
Problems(2)
Problem 6 IMC 2004 Macedonia
Source:
7/25/2004
For every complex number different from 0 and 1 we define the following function
where the sum is over all branches of the complex logarithm.
a) Prove that there are two polynomials and such that for all .
b) Prove that for all we have
functionlogarithmsalgebrapolynomialcalculusderivativeintegration
Problem 12 IMC 2004 Macedonia
Source:
7/26/2004
For define the matrices and as follows: A_0 \equal{} B_0 \equal{} (1), and for every let
A_n \equal{} \left( \begin{array}{cc} A_{n \minus{} 1} & A_{n \minus{} 1} \\
A_{n \minus{} 1} & B_{n \minus{} 1} \\
\end{array} \right) \ \textrm{and} \ B_n \equal{} \left( \begin{array}{cc} A_{n \minus{} 1} & A_{n \minus{} 1} \\
A_{n \minus{} 1} & 0 \\
\end{array} \right).
Denote by the sum of all the elements of a matrix . Prove that S(A_n^{k \minus{} 1}) \equal{} S(A_k^{n \minus{} 1}), for all .
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