Let I and J be intervals. Let φ,ψ:I→R be strictly increasing continuous functions and let Φ,Ψ:J→R be continuous functions. Suppose that φ(x)+ψ(x)=x and Φ(u)+Ψ(u)=u holds for all x∈I and u∈J. Show that if f:I→J is a continuous solution of the functional inequality
f(φ(x)+ψ(y))≤Φ(f(x))+Ψ(f(y))(x,y∈I),then Φ∘f∘φ−1 and Ψ∘f∘ψ−1 are convex functions. algebraFunctional inequalityconvex functionfunctioninterval