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Putnam
1946 Putnam
A3
A3
Part of
1946 Putnam
Problems
(1)
Putnam 1946 A3
Source: Putnam 1946
3/13/2022
A projectile in flight is observed simultaneously from four radio stations which are situated at the corners of a square of side
b
b
b
. The distances of the projectile from the four stations, taken in order around the square, are found to be
R
1
,
R
2
,
R
3
R_1 , R_2 , R_3
R
1
,
R
2
,
R
3
and
R
4
R_4
R
4
. Show that
R
1
2
+
R
3
2
=
R
2
2
+
R
4
2
.
R_{1}^{2}+ R_{3}^{2}= R_{2}^{2}+ R_{4}^{2}.
R
1
2
+
R
3
2
=
R
2
2
+
R
4
2
.
Show also that the height
h
h
h
of the projectile above the ground is given by
h
2
=
−
1
2
b
2
+
1
4
(
R
1
2
+
R
2
2
+
R
3
2
+
R
4
2
)
−
1
8
b
2
(
R
1
4
+
R
2
4
+
R
3
4
+
R
4
4
−
2
R
1
2
R
3
2
−
2
R
2
2
R
4
2
)
.
h^{2}=- \frac{1}{2} b^2 +\frac{1}{4}(R_{1}^{2}+R_{2}^{2}+R_{3}^{2}+R_{4}^{2}) -\frac{1}{8 b^{2}}(R_{1}^{4}+R_{2}^{4}+R_{3}^{4}+R_{4}^{4}- 2 R_{1}^{2}R_{3}^{2} -2 R_{2}^{2} R_{4}^{2}).
h
2
=
−
2
1
b
2
+
4
1
(
R
1
2
+
R
2
2
+
R
3
2
+
R
4
2
)
−
8
b
2
1
(
R
1
4
+
R
2
4
+
R
3
4
+
R
4
4
−
2
R
1
2
R
3
2
−
2
R
2
2
R
4
2
)
.
Putnam
3D geometry