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Perfect powers with divisor-function-like exponent

Source: Mexico National Olympiad 2019 Problem 1

November 12, 2019
number theorynumber of divisorsPerfect powerfunction

Problem Statement

An integer number m1m\geq 1 is mexica if it's of the form nd(n)n^{d(n)}, where nn is a positive integer and d(n)d(n) is the number of positive integers which divide nn. Find all mexica numbers less than 20192019.
Note. The divisors of nn include 11 and nn; for example, d(12)=6d(12)=6, since 1,2,3,4,6,121, 2, 3, 4, 6, 12 are all the positive divisors of 1212.
Proposed by Cuauhtémoc Gómez