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AZE JBMO TST

Source: AZE JBMO TST

May 2, 2015

geometrycircumcirclesymmetry

Problem Statement

There is a triangle

ABC

that

AB

is not equal to

AC

.

BD

is interior bisector of

\angle{ABC}

(

D\in AC

)

M

is midpoint of

CBA

arc.Circumcircle of

\triangle{BDM}

cuts

AB

at

K

and

J,

is symmetry of

A

according

K

.If

DJ\cap AM=(O)

, Prove that

J,B,M,O

are cyclic.

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