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1\p=1/a^2+1/b^2 diophantine with prime p (Greece Juniors 2017 p3)

Source:

March 16, 2020
Diophantine equationdiophantinenumber theory

Problem Statement

Find all triplets (a,b,p)(a,b,p) where a,ba,b are positive integers and pp is a prime number satisfying: 1p=1a2+1b2\frac{1}{p}=\frac{1}{a^2}+\frac{1}{b^2}