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n^3 - 18n^2 + 115n - 391 a perfect cube

Source: 1989 Swedish Mathematical Competition p3

March 28, 2021
Perfect Squarenumber theorygeometry3D geometry

Problem Statement

Find all positive integers nn such that n3−18n2+115n−391n^3 - 18n^2 + 115n - 391 is the cube of a positive intege
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