Source: 1986 National High School Mathematics League, Exam One, Problem 1
February 24, 2020
functioninequalities
Problem Statement
Let −1<a<0, θ=arcsina. Then the solution set to the inequality sinx<a is
(A){x∣2nπ+θ<x<(2n+1)π−θ,n∈Z}(B){x∣2nπ−θ<x<(2n+1)π+θ,n∈Z}(C){x∣(2n−1)π+θ<x<2nπ−θ,n∈Z}(D){x∣(2n−1)π−θ<x<2nπ+θ,n∈Z}