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The segments divide the parallelogram into four triangles

Source: Austrian Mathematical Olympiad 2003, Part 1, P4

June 18, 2011
geometryparallelogramratiogeometry proposed

Problem Statement

In a parallelogram ABCDABCD, points EE and FF are the midpoints of ABAB and BCBC, respectively, and PP is the intersection of ECEC and FDFD. Prove that the segments AP,BP,CPAP,BP,CP and DPDP divide the parallelogram into four triangles whose areas are in the ratio 1:2:3:41 : 2 : 3 : 4.