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in n^2-9 has 6 positive divisors than GCD (n-3, n+3)=1

Source: Greece JBMO TST 2016 p3

April 29, 2019
number theorygreatest common divisorDivisors

Problem Statement

Positive integer nn is such that number n2−9n^2-9 has exactly 66 positive divisors. Prove that GCD (n−3,n+3)=1(n-3, n+3)=1
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