MathDB
Simple and nice problem

Source:

March 11, 2018
number theory

Problem Statement

a,ba,b are natural numbers such that a+1b\frac{a+1}{b} and b+1a\frac{b+1}{a} are integers.Let d=GCD(a;b)d=GCD(a;b).Prove that d2a+bd^2\le a+b