MathDB
Today's calculation of Integral 145

Source: Yamagata University entrance exam 1980

August 28, 2006
calculusintegrationlogarithmsabsolute valuecalculus computations

Problem Statement

Find the minimum value of xx+l(t+1t)dt (x>0, l>0).\int_{x}^{x+l}\left(t+\frac{1}{t}\right)dt \ (x>0,\ l>0).