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<CBD=? right isosceles ABC, AB = BD 2018-19 Dürer Round1 D4

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December 1, 2022
anglesgeometryright triangle

Problem Statement

Let ABCABC be an isosceles right-angled triangle, having the right angle at vertex CC. Let us consider the line through CC which is parallel to ABAB and let DD be a point on this line such that AB=BDAB = BD and DD is closer to BB than to AA. Find the angle ∠CBD\angle CBD.
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