Let ABCD be a rhombus such that m(ABC)=40∘. Let E be the midpoint of [BC] and F be the foot of the perpendicular from A to DE. What is m(DFC)?<spanclass=′latex−bold′>a)</span>100∘<spanclass=′latex−bold′>b)</span>110∘<spanclass=′latex−bold′>c)</span>115∘<spanclass=′latex−bold′>d)</span>120∘<spanclass=′latex−bold′>e)</span>135∘