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similar triangles on sides of a ABCD with perpendicular diagonals

Source: 2013 Oral Moscow Geometry Olympiad grades 10-11 p4

August 17, 2019
geometrysimilar trianglesperpendiculardiagonalsequal segments

Problem Statement

Similar triangles ABM,CBP,CDLABM, CBP, CDL and ADKADK are built on the sides of the quadrilateral ABCDABCD with perpendicular diagonals in the outer side (the neighboring ones are oriented differently). Prove that PK=MLPK = ML.