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p(a)=b, p(b)=c, p(c)=a not possible for integer cubic (1995 Chile NMO P3)

Source:

November 22, 2021
algebrapolynomialCubic

Problem Statement

If p(x)=c0+c1x+c2x2+c3x3p (x) = c_0 + c_1x + c_2x^2 + c_3x^3 is a polynomial with integer coefficients with a,b,ca, b,c integers and different from each other, prove that it cannot happen simultaneously that p(a)=bp (a) = b, p(b)=cp (b) = c and p(c)=ap (c) = a.