MathDB
geometry

Source:

January 31, 2016
geometry

Problem Statement

Let CC is at a circle. [AB][AB] is a diameter this circle. DD is a point at [AB][AB]. Perpendicular from CC to [AB][AB]'s foot on the [AB][AB] is EE, perpendicular from AA to [CD][CD]'s foot on the [CD][CD] is FF. Prove that, [DC][FC]=[BD][EA][DC][FC]=[BD][EA]