MathDB
Find a number n in the system of base n^2 + 1

Source:

October 7, 2010
number theory unsolvednumber theory

Problem Statement

In the system of base n2+1n^2 + 1 find a number NN with nn different digits such that:
(i) NN is a multiple of nn. Let N=nN.N = nN'.
(ii) The number NN and NN' have the same number nn of different digits in base n2+1n^2 + 1, none of them being zero.
(iii) If s(C)s(C) denotes the number in base n2+1n^2 + 1 obtained by applying the permutation ss to the nn digits of the number CC, then for each permutation s,s(N)=ns(N).s, s(N) = ns(N').