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Easy sequence

Source: Bosnia and Herzegovina TST 2014 day 2 problem 1

May 11, 2014
algebra solvedalgebra

Problem Statement

Sequence ana_n is defined by a1=12a_1=\frac{1}{2}, am=am12mam1+1a_m=\frac{a_{m-1}}{2m \cdot a_{m-1} + 1} for m>1m>1. Determine value of a1+a2+...+aka_1+a_2+...+a_k in terms of kk, where kk is positive integer.